What is inverse oflaplace 8/(s^2+64) ?

The answer to inverse oflaplace 8/(s^2+64) is sin(8t)

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inverse oflaplace 8/(s^2+64)

inverse laplace

\frac{8}{s ^{2} + 64}

sin (8 t)

Solution steps

L^{- 1} {\frac{8}{s ^{2} + 64}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s ^{2} + a ^{2}}} = sin (a t)

L^{- 1} {\frac{8}{s ^{2} + 8 ^{2}}} = sin (8 t)

= sin (8 t)

\int (4 x^{3} + 6 x^{2} - 1) d x

\int csc (\frac{x}{2}) d x

\frac{\partial}{\partial y} (10 x y)

\frac{1}{x ^{2} - 2 x - 3}

x \to 4 lim (\frac{1}{x + 4})

What is inverse oflaplace 8/(s^2+64) ?
The answer to inverse oflaplace 8/(s^2+64) is sin(8t)