What is the derivative of 1/(x^2-2x-3) ?

The derivative of 1/(x^2-2x-3) is -(2x-2)/((x^2-2x-3)^2)

What is the first derivative of 1/(x^2-2x-3) ?

The first derivative of 1/(x^2-2x-3) is -(2x-2)/((x^2-2x-3)^2)

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derivative of

\frac{1}{x ^{2} - 2 x - 3}

- \frac{2 x - 2}{( x ^{2} - 2 x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{2} - 2 x - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x^{2} - 2 x - 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} - 2 x - 3 ) ^{2}} \frac{d}{d x} (x^{2} - 2 x - 3)

= - \frac{1}{( x ^{2} - 2 x - 3 ) ^{2}} \frac{d}{d x} (x^{2} - 2 x - 3)

\frac{d}{d x} (x^{2} - 2 x - 3) = 2 x - 2

= - \frac{1}{( x ^{2} - 2 x - 3 ) ^{2}} (2 x - 2)

Simplify

- \frac{1}{( x ^{2} - 2 x - 3 ) ^{2}} (2 x - 2) : - \frac{2 x - 2}{( x ^{2} - 2 x - 3 ) ^{2}}

= - \frac{2 x - 2}{( x ^{2} - 2 x - 3 ) ^{2}}

x \to 4 lim (\frac{1}{x + 4})

\int sin^{11} (x) cos^{5} (x) d x

\int (\frac{19.8}{x} - 9 x^{2}) d x

y^{^{''}} + 8 y^{^{'}} + 20 y = 0, y (0) = 0, y^{^{'}} (0) = 0

\int_{1}^{2} x (2 - x) d x

What is the derivative of 1/(x^2-2x-3) ?
The derivative of 1/(x^2-2x-3) is -(2x-2)/((x^2-2x-3)^2)
What is the first derivative of 1/(x^2-2x-3) ?
The first derivative of 1/(x^2-2x-3) is -(2x-2)/((x^2-2x-3)^2)