What is the solution for y^{''}+8y^'+20y=0,y(0)=0,y^'(0)=0 ?

The solution for y^{''}+8y^'+20y=0,y(0)=0,y^'(0)=0 is y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+8y^'+20y=0,y(0)=0,y^'(0)=0

y^{^{''}} + 8 y^{^{'}} + 20 y = 0, y (0) = 0, y^{^{'}} (0) = 0

y = 0

Solution steps

y^{''} (t) + 8 y^{'} (t) + 20 y = 0

Solve linear ODE:

y = 0

y = 0

\int_{1}^{2} x (2 - x) d x

\int_{0}^{1} \frac{85}{x ^{5}} d x

\frac{d}{d x} (\frac{x}{9 + x})

f (x) = x^{2} + 10

\int sin^{2} (\frac{x}{4}) d x

What is the solution for y^{''}+8y^'+20y=0,y(0)=0,y^'(0)=0 ?
The solution for y^{''}+8y^'+20y=0,y(0)=0,y^'(0)=0 is y=0