What is the d/(dθ)(cot^2(sin(θ))) ?

The d/(dθ)(cot^2(sin(θ))) is -2csc^2(sin(θ))cot(sin(θ))cos(θ)

What is the first d/(dθ)(cot^2(sin(θ))) ?

The first d/(dθ)(cot^2(sin(θ))) is -2csc^2(sin(θ))cot(sin(θ))cos(θ)

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\frac{d}{d θ} (cot^{2} (sin (θ)))

- 2 csc^{2} (sin (θ)) cot (sin (θ)) cos (θ)

Solution steps

\frac{d}{d θ} (cot^{2} (sin (θ)))

Apply the chain rule:

2 cot (sin (θ)) \frac{d}{d θ} (cot (sin (θ)))

= 2 cot (sin (θ)) \frac{d}{d θ} (cot (sin (θ)))

\frac{d}{d θ} (cot (sin (θ))) = - csc^{2} (sin (θ)) cos (θ)

= 2 cot (sin (θ)) (- csc^{2} (sin (θ)) cos (θ))

Simplify

= - 2 csc^{2} (sin (θ)) cot (sin (θ)) cos (θ)

5 (ln (y)) y^{^{'}} - x^{3} y = 0

\int 8 tan (x) sec^{4} (x) d x

(tan (\frac{x}{2}))^{^{'}}

t \to 0 lim (t (ln (t)))

\int_{- 1}^{0} x 1 - x^{2} d x

What is the d/(dθ)(cot^2(sin(θ))) ?
The d/(dθ)(cot^2(sin(θ))) is -2csc^2(sin(θ))cot(sin(θ))cos(θ)
What is the first d/(dθ)(cot^2(sin(θ))) ?
The first d/(dθ)(cot^2(sin(θ))) is -2csc^2(sin(θ))cot(sin(θ))cos(θ)