What is (\partial ^2)/(\partial r\partial θ)(r(θ)cos(θ)) ?

The answer to (\partial ^2)/(\partial r\partial θ)(r(θ)cos(θ)) is cos(θ)-θsin(θ)

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(\partial ^2)/(\partial r\partial θ)(r(θ)cos(θ))

\frac{\partial ^{2}}{\partial r \partial θ} (r (θ) cos (θ))

cos (θ) - θ sin (θ)

Solution steps

\frac{\partial ^{2}}{\partial r \partial θ} (r (θ) cos (θ))

\frac{\partial}{\partial r} (r θ cos (θ)) = θ cos (θ)

= \frac{\partial}{\partial θ} (θ cos (θ))

\frac{\partial}{\partial θ} (θ cos (θ)) = cos (θ) - θ sin (θ)

= cos (θ) - θ sin (θ)

x \to 0 lim (\frac{x ^{2} + 1}{x - 1})

(x + y + 1) d x - (y - x + 3) d y = 0

x \to - 1 lim (7 ∣ x + 1 ∣ - 4)

\int e^{2 x} d x

\int \frac{x ( 6 x ^{2} + 6 )}{x ^{2} + 1} d x

What is (\partial ^2)/(\partial r\partial θ)(r(θ)cos(θ)) ?
The answer to (\partial ^2)/(\partial r\partial θ)(r(θ)cos(θ)) is cos(θ)-θsin(θ)