What is the derivative of (14x+8x^2)/((7+8x)^2) ?

The derivative of (14x+8x^2)/((7+8x)^2) is (98)/((7+8x)^3)

What is the first derivative of (14x+8x^2)/((7+8x)^2) ?

The first derivative of (14x+8x^2)/((7+8x)^2) is (98)/((7+8x)^3)

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derivative of

\frac{14 x + 8 x ^{2}}{( 7 + 8 x ) ^{2}}

\frac{98}{( 7 + 8 x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{14 x + 8 x ^{2}}{( 7 + 8 x ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 14 x + 8 x ^{2} ) ( 7 + 8 x ) ^{2} - \frac{d}{d x} ( ( 7 + 8 x ) ^{2} ) ( 14 x + 8 x ^{2} )}{( ( 7 + 8 x ) ^{2} ) ^{2}}

\frac{d}{d x} (14 x + 8 x^{2}) = 14 + 16 x

\frac{d}{d x} ((7 + 8 x)^{2}) = 16 (7 + 8 x)

= \frac{( 14 + 16 x ) ( 7 + 8 x ) ^{2} - 16 ( 7 + 8 x ) ( 14 x + 8 x ^{2} )}{( ( 7 + 8 x ) ^{2} ) ^{2}}

Simplify

\frac{( 14 + 16 x ) ( 7 + 8 x ) ^{2} - 16 ( 7 + 8 x ) ( 14 x + 8 x ^{2} )}{( ( 7 + 8 x ) ^{2} ) ^{2}} : \frac{98}{( 7 + 8 x ) ^{3}}

= \frac{98}{( 7 + 8 x ) ^{3}}

\frac{d}{d t} x + 7 x = 5 cos (2 t)

\int_{1}^{3} x 3^{x^{2}} d x

g (x) = 27 x^{2} - x^{3}

y = 4 - 9 x^{2}, (- 3, - 77)

\int \frac{3 x}{x ^{4} + 1} d x

What is the derivative of (14x+8x^2)/((7+8x)^2) ?
The derivative of (14x+8x^2)/((7+8x)^2) is (98)/((7+8x)^3)
What is the first derivative of (14x+8x^2)/((7+8x)^2) ?
The first derivative of (14x+8x^2)/((7+8x)^2) is (98)/((7+8x)^3)