What is the derivative of (x^6/6+1/(16x^4)) ?

The derivative of (x^6/6+1/(16x^4)) is x^5-1/(4x^5)

What is the first derivative of (x^6/6+1/(16x^4)) ?

The first derivative of (x^6/6+1/(16x^4)) is x^5-1/(4x^5)

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\frac{d}{d x} (\frac{x ^{6}}{6} + \frac{1}{16 x ^{4}})

x^{5} - \frac{1}{4 x ^{5}}

Solution steps

\frac{d}{d x} (\frac{x ^{6}}{6} + \frac{1}{16 x ^{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{6}}{6}) + \frac{d}{d x} (\frac{1}{16 x ^{4}})

\frac{d}{d x} (\frac{x ^{6}}{6}) = x^{5}

\frac{d}{d x} (\frac{1}{16 x ^{4}}) = - \frac{1}{4 x ^{5}}

= x^{5} - \frac{1}{4 x ^{5}}

cos (10 x) - 1

x \to 0 lim (\frac{sin ( 5 x )}{sin ( 9 x )})

\int x (3 x^{2} - 5) d x

3 x^{2} - 2 y^{3} \frac{d y}{d x} = 0

\frac{\partial}{\partial y} (x^{2} - y^{2})

What is the derivative of (x^6/6+1/(16x^4)) ?
The derivative of (x^6/6+1/(16x^4)) is x^5-1/(4x^5)
What is the first derivative of (x^6/6+1/(16x^4)) ?
The first derivative of (x^6/6+1/(16x^4)) is x^5-1/(4x^5)