What is the solution for 3x^2-2y^3(dy)/(dx)=0 ?

The solution for 3x^2-2y^3(dy)/(dx)=0 is y=\sqrt[4]{2x^3+c_{1}},y=-\sqrt[4]{2x^3+c_{1}}

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3x^2-2y^3(dy)/(dx)=0

3 x^{2} - 2 y^{3} \frac{d y}{d x} = 0

Solution steps

3 x^{2} - 2 y^{3} \frac{d y}{d x} = 0

Solve separable ODE:

\frac{\partial}{\partial y} (x^{2} - y^{2})

\int x^{2} + 4 x + 3 d x

\int \frac{sec ( x )}{1 - tan ( x )} d x

\frac{d}{d x} ((x^{3} - 7) (2 x^{2} + 3))

(2 x + 4)^{^{'}}

What is the solution for 3x^2-2y^3(dy)/(dx)=0 ?
The solution for 3x^2-2y^3(dy)/(dx)=0 is y=\sqrt[4]{2x^3+c_{1}},y=-\sqrt[4]{2x^3+c_{1}}