What is (\partial)/(\partial y)(2+3x+4y) ?

The answer to (\partial)/(\partial y)(2+3x+4y) is 4

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(\partial)/(\partial y)(2+3x+4y)

\frac{\partial}{\partial y} (2 + 3 x + 4 y)

4

Solution steps

\frac{\partial}{\partial y} (2 + 3 x + 4 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2) + \frac{\partial}{\partial y} (3 x) + \frac{\partial}{\partial y} (4 y)

\frac{\partial}{\partial y} (2) = 0

\frac{\partial}{\partial y} (3 x) = 0

\frac{\partial}{\partial y} (4 y) = 4

= 0 + 0 + 4

Simplify

= 4

\int \frac{35}{1 - cos ( 7 x )} d x

\int \frac{x ^{3} - 7}{x} d x

\int arctan (\frac{sin ( x )}{1 + cos ( x )}) d x

(\frac{x ^{2} + 4}{x ^{2} - 4})^{4}

\frac{d y}{d x} = (y - 1)^{3}

What is (\partial)/(\partial y)(2+3x+4y) ?
The answer to (\partial)/(\partial y)(2+3x+4y) is 4