What is the solution for (dy)/(dx)=(y-1)^3 ?

The solution for (dy)/(dx)=(y-1)^3 is y=sqrt(-1/(2(x+c_{1)))}+1,y=-sqrt(-1/(2(x+c_{1)))}+1

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(dy)/(dx)=(y-1)^3

\frac{d y}{d x} = (y - 1)^{3}

y = - \frac{1}{2 ( x + c _{1} )} + 1, y = - - \frac{1}{2 ( x + c _{1} )} + 1

Solution steps

\frac{d y}{d x} = (y - 1)^{3}

Solve separable ODE:

y = - \frac{1}{2 ( x + c _{1} )} + 1, y = - - \frac{1}{2 ( x + c _{1} )} + 1

y = - \frac{1}{2 ( x + c _{1} )} + 1, y = - - \frac{1}{2 ( x + c _{1} )} + 1

y = \frac{4 x + 5}{x - 1}, (2, 13)

\frac{d}{d x} (a sec (x))

\int \frac{ln ( x ^{6} )}{x} d x

\int e^{- s t} cos (b t) d t

\int \frac{1}{x + 3} d x

What is the solution for (dy)/(dx)=(y-1)^3 ?
The solution for (dy)/(dx)=(y-1)^3 is y=sqrt(-1/(2(x+c_{1)))}+1,y=-sqrt(-1/(2(x+c_{1)))}+1