What is the integral from 0 to 5 of 0.2x ?

The integral from 0 to 5 of 0.2x is 2.5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 5 of 0.2x

\int_{0}^{5} 0.2 x d x

2.5

Solution steps

\int_{0}^{5} 0.2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.2 \cdot \int_{0}^{5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{5}

= 0.2 [\frac{x ^{2}}{2}]_{0}^{5}

Simplify

= 0.2 [0.5 x^{2}]_{0}^{5}

Compute the boundaries:

12.5

= 0.2 \cdot 12.5

Simplify

= 2.5

n = 1 \sum \infty n (n + 1)

x \to 3 lim (x^{2} - 3 x)

\int (a^{\frac{2}{3}} - x^{\frac{2}{3}})^{2} d x

\int cos^{2} (6 x) sin^{3} (6 x) d x

\int \frac{10}{5 - x} d x

What is the integral from 0 to 5 of 0.2x ?
The integral from 0 to 5 of 0.2x is 2.5