What is the solution for (dy}{dx}=\frac{(y+sqrt(x^2+y^2)))/x ?

The solution for (dy}{dx}=\frac{(y+sqrt(x^2+y^2)))/x is y=-1/(2e^{c_{1)}}+(e^{c_{1}}x^2)/2

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(dy}{dx}=\frac{(y+sqrt(x^2+y^2)))/x

\frac{d y}{d x} = \frac{( y + x ^{2} + y ^{2} )}{x}

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

Solution steps

\frac{d y}{d x} = \frac{( y + x ^{2} + y ^{2} )}{x}

Solve using substitution:

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

\frac{x - 2}{2 ( x - 1 ) ^{\frac{3}{2}}}

n = 1 \sum \infty (2 n + 1)^{- 5}

\frac{\partial}{\partial x} (ln (1 - x^{2}))

x \to 4 - lim (\frac{2}{x ^{2} - 16})

\frac{3}{1 + x - 2 x ^{2}}

What is the solution for (dy}{dx}=\frac{(y+sqrt(x^2+y^2)))/x ?
The solution for (dy}{dx}=\frac{(y+sqrt(x^2+y^2)))/x is y=-1/(2e^{c_{1)}}+(e^{c_{1}}x^2)/2