What is (\partial)/(\partial x)(-3sin(2x)) ?

The answer to (\partial)/(\partial x)(-3sin(2x)) is -6cos(2x)

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(\partial)/(\partial x)(-3sin(2x))

\frac{\partial}{\partial x} (- 3 sin (2 x))

- 6 cos (2 x)

Solution steps

\frac{\partial}{\partial x} (- 3 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= - 3 cos (2 x) \cdot 2

Simplify

= - 6 cos (2 x)

\frac{d}{d x} (2 a sin (x))

y^{^{'}} + 4 y = e^{- x}

\int \frac{1 + x ^{2}}{1 + y ^{2}} d x

(x^{2} + 3 y^{2}) d x - 2 x y d y = 0

\int \frac{e ^{2 x}}{1 + e ^{x}} d x

What is (\partial)/(\partial x)(-3sin(2x)) ?
The answer to (\partial)/(\partial x)(-3sin(2x)) is -6cos(2x)