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Popular >

area f(x)=-x^3+8,-8,1

Solution

area

f (x) = - x^{3} + 8, - 8, 1

Solution

\frac{4383}{4}

+1

Decimal Notation

1095.75

Solution steps

Apply the area formula:

\int_{- 8}^{1} - x^{3} + 8 d x

Solve

\int_{- 8}^{1} - x^{3} + 8 d x : \frac{4383}{4}

The area is:

= \frac{4383}{4}

Popular Examples

integral of-x^2-x

\int - x^{2} - x d x

integral of (ln(y^3))/(8y)

\int \frac{ln ( y ^{3} )}{8 y} d y

tangent of f(x)=x^2+3x-1,\at x=-1 tangent of

f (x) = x^{2} + 3 x - 1, at x = - 1

integral of 1/(xsqrt(9x^2-49))

\int \frac{1}{x 9 x ^{2} - 49} d x

derivative of 1/((1+x^3))

\frac{d}{d x} (\frac{1}{( 1 + x ) ^{3}})

Frequently Asked Questions (FAQ)

What is area f(x)=-x^3+8,-8,1 ?
The answer to area f(x)=-x^3+8,-8,1 is 4383/4