What is the derivative of x^2-16x ?

The derivative of x^2-16x is 2x-16

What is the first derivative of x^2-16x ?

The first derivative of x^2-16x is 2x-16

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\frac{d}{d x} (x^{2} - 16 x)

2 x - 16

Solution steps

\frac{d}{d x} (x^{2} - 16 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (16 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (16 x) = 16

= 2 x - 16

- 7 e^{(x + 2)} + e^{5}

(6, - 7), (8, 5)

\frac{\partial}{\partial y} (4 y^{2} - 20)

f (x) = 8 ln (x) - x^{2}

\frac{d y}{d x} = 10 - 2 y

What is the derivative of x^2-16x ?
The derivative of x^2-16x is 2x-16
What is the first derivative of x^2-16x ?
The first derivative of x^2-16x is 2x-16