What is the derivative of (3x-4^5) ?

The derivative of (3x-4^5) is 15(3x-4)^4

What is the first derivative of (3x-4^5) ?

The first derivative of (3x-4^5) is 15(3x-4)^4

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\frac{d}{d x} ((3 x - 4)^{5})

15 (3 x - 4)^{4}

Solution steps

\frac{d}{d x} ((3 x - 4)^{5})

Apply the chain rule:

5 (3 x - 4)^{4} \frac{d}{d x} (3 x - 4)

= 5 (3 x - 4)^{4} \frac{d}{d x} (3 x - 4)

\frac{d}{d x} (3 x - 4) = 3

= 5 (3 x - 4)^{4} \cdot 3

Simplify

= 15 (3 x - 4)^{4}

f (t) = sin (t) - t cos (t)

x^{2} y^{^{'}} - 2 x y = 4 y^{4}

\int (2 x + 6) d x

x^{2} - x - 1

f (x) = 2 x^{3} - x^{2} + 6, at x = 2

What is the derivative of (3x-4^5) ?
The derivative of (3x-4^5) is 15(3x-4)^4
What is the first derivative of (3x-4^5) ?
The first derivative of (3x-4^5) is 15(3x-4)^4