What is the derivative of x^2-x-1 ?

The derivative of x^2-x-1 is 2x-1

What is the first derivative of x^2-x-1 ?

The first derivative of x^2-x-1 is 2x-1

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derivative of

x^{2} - x - 1

2 x - 1

Solution steps

\frac{d}{d x} (x^{2} - x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 2 x - 1 - 0

Simplify

= 2 x - 1

f (x) = 2 x^{3} - x^{2} + 6, at x = 2

\int \frac{e ^{x}}{4 - e ^{2 x}} d x

g (x) = 7 + 4 x

\frac{d}{d x} (\frac{5 x}{x ^{2} + 6})

\frac{3 V}{π \cdot r ^{2}}

What is the derivative of x^2-x-1 ?
The derivative of x^2-x-1 is 2x-1
What is the first derivative of x^2-x-1 ?
The first derivative of x^2-x-1 is 2x-1