What is the derivative of g(x)=sqrt(7+4x) ?

The derivative of g(x)=sqrt(7+4x) is 2/(sqrt(7+4x))

What is the first derivative of g(x)=sqrt(7+4x) ?

The first derivative of g(x)=sqrt(7+4x) is 2/(sqrt(7+4x))

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derivative of

g (x) = 7 + 4 x

\frac{2}{7 + 4 x}

Solution steps

\frac{d}{d x} (7 + 4 x)

Apply the chain rule:

\frac{1}{2 7 + 4 x} \frac{d}{d x} (7 + 4 x)

= \frac{1}{2 7 + 4 x} \frac{d}{d x} (7 + 4 x)

\frac{d}{d x} (7 + 4 x) = 4

= \frac{1}{2 7 + 4 x} \cdot 4

Simplify

\frac{1}{2 7 + 4 x} \cdot 4 : \frac{2}{7 + 4 x}

= \frac{2}{7 + 4 x}

\frac{d}{d x} (\frac{5 x}{x ^{2} + 6})

\frac{3 V}{π \cdot r ^{2}}

x \to 0 lim (ln (e^{x}))

\frac{d}{d x} (ln (s) in x)

y^{^{'}} + tan (3 x) y = 0, y (0) = 3

What is the derivative of g(x)=sqrt(7+4x) ?
The derivative of g(x)=sqrt(7+4x) is 2/(sqrt(7+4x))
What is the first derivative of g(x)=sqrt(7+4x) ?
The first derivative of g(x)=sqrt(7+4x) is 2/(sqrt(7+4x))