What is the integral from 4 to infinity of e^{-x} ?

The integral from 4 to infinity of e^{-x} is 1/(e^4)

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integral from 4 to infinity of e^{-x}

\int_{4}^{\infty} e^{- x} d x

\frac{1}{e ^{4}}

Decimal Notation

0.01831 \dots

Solution steps

\int_{4}^{\infty} e^{- x} d x

Compute the indefinite integral:

\int e^{- x} d x = - e^{- x} + C

Compute the boundaries:

\int_{4}^{\infty} e^{- x} d x = 0 - (- \frac{1}{e ^{4}})

= 0 - (- \frac{1}{e ^{4}})

Simplify

= \frac{1}{e ^{4}}

f (x) = 2 x e^{x} csc (x)

\frac{d}{d x} (sec^{2} (\frac{x}{2}))

\frac{d}{d x} (\frac{2 - x ^{2}}{3 x ^{2} + 1})

x \to - 1 + lim (\frac{x ^{2} + x}{x + 1})

\frac{d}{d x} (x^{2} \cdot x^{7})

What is the integral from 4 to infinity of e^{-x} ?
The integral from 4 to infinity of e^{-x} is 1/(e^4)