What is the derivative of sin(x)+7/4 cot(x) ?

The derivative of sin(x)+7/4 cot(x) is cos(x)-7/4 csc^2(x)

What is the first derivative of sin(x)+7/4 cot(x) ?

The first derivative of sin(x)+7/4 cot(x) is cos(x)-7/4 csc^2(x)

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derivative of

sin (x) + \frac{7}{4} cot (x)

cos (x) - \frac{7}{4} csc^{2} (x)

Solution steps

\frac{d}{d x} (sin (x) + \frac{7}{4} cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x)) + \frac{d}{d x} (\frac{7}{4} cot (x))

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (\frac{7}{4} cot (x)) = - \frac{7}{4} csc^{2} (x)

= cos (x) - \frac{7}{4} csc^{2} (x)

\frac{x ^{2}}{x + 7}

\frac{1}{s ^{3} + s ^{4}}

\frac{d}{d x} (5 x tan (x))

y^{^{'}} = t + t y^{2}, y (2) = 0

\frac{d}{d x} (\frac{12}{x ^{3}})

What is the derivative of sin(x)+7/4 cot(x) ?
The derivative of sin(x)+7/4 cot(x) is cos(x)-7/4 csc^2(x)
What is the first derivative of sin(x)+7/4 cot(x) ?
The first derivative of sin(x)+7/4 cot(x) is cos(x)-7/4 csc^2(x)