What is the limit as x approaches 0 of (x^2+8)/(x-1) ?

The limit as x approaches 0 of (x^2+8)/(x-1) is -8

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limit as x approaches 0 of (x^2+8)/(x-1)

x \to 0 lim (\frac{x ^{2} + 8}{x - 1})

- 8

Solution steps

x \to 0 lim (\frac{x ^{2} + 8}{x - 1})

Plug in the value

x = 0

= \frac{0 ^{2} + 8}{0 - 1}

Simplify

\frac{0 ^{2} + 8}{0 - 1} : - 8

= - 8

\frac{d}{d x} ((3 x - 1) (2 x + 5))

x^{^{''}} - 14 x^{^{'}} + 49 x = 4 t e^{7 t}

x^{3} + 4 x

\frac{\partial}{\partial y} (x^{2} - x + g (y))

\frac{d y}{d x} = (\frac{y}{( x + 2 y )})

What is the limit as x approaches 0 of (x^2+8)/(x-1) ?
The limit as x approaches 0 of (x^2+8)/(x-1) is -8