What is (d^4)/(dx^4)((10x)/(1-x)) ?

The answer to (d^4)/(dx^4)((10x)/(1-x)) is (240)/((1-x)^5)

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(d^4)/(dx^4)((10x)/(1-x))

\frac{d ^{4}}{d x ^{4}} (\frac{10 x}{1 - x})

\frac{240}{( 1 - x ) ^{5}}

Solution steps

\frac{d ^{4}}{d x ^{4}} (\frac{10 x}{1 - x})

\frac{d}{d x} (\frac{10 x}{1 - x}) = \frac{10}{( 1 - x ) ^{2}}

= \frac{d ^{3}}{d x ^{3}} (\frac{10}{( 1 - x ) ^{2}})

\frac{d}{d x} (\frac{10}{( 1 - x ) ^{2}}) = \frac{20}{( 1 - x ) ^{3}}

= \frac{d ^{2}}{d x ^{2}} (\frac{20}{( 1 - x ) ^{3}})

\frac{d}{d x} (\frac{20}{( 1 - x ) ^{3}}) = \frac{60}{( 1 - x ) ^{4}}

= \frac{d}{d x} (\frac{60}{( 1 - x ) ^{4}})

\frac{d}{d x} (\frac{60}{( 1 - x ) ^{4}}) = \frac{240}{( 1 - x ) ^{5}}

= \frac{240}{( 1 - x ) ^{5}}

f (x) = e^{5 x^{2}}

y = sin (2 x), at x = \frac{π}{2}

2 x^{2} + 3 x - 2, at x = 0

f (x) = \frac{3}{x ^{2}} + \frac{5}{x ^{4}}

\frac{d y}{d x} = 4 x + \frac{4 x}{16 - x ^{2}}

What is (d^4)/(dx^4)((10x)/(1-x)) ?
The answer to (d^4)/(dx^4)((10x)/(1-x)) is (240)/((1-x)^5)