What is maclaurin ln((1+x)/(1-x)) ?

The answer to maclaurin ln((1+x)/(1-x)) is 2x+2/3 x^3+2/5 x^5+\ldots

Popular >

maclaurin ln((1+x)/(1-x))

maclaurin

ln (\frac{1 + x}{1 - x})

2 x + \frac{2}{3} x^{3} + \frac{2}{5} x^{5} + \dots

Solution steps

Apply the Maclaurin Formula

= 0 + \frac{\frac{d}{d x} ( ln ( \frac{1 + x}{1 - x} ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( ln ( \frac{1 + x}{1 - x} ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( ln ( \frac{1 + x}{1 - x} ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{2}{1 !} x + \frac{0}{2 !} x^{2} + \frac{4}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{48}{5 !} x^{5} + \dots

Refine

= 2 x + \frac{2}{3} x^{3} + \frac{2}{5} x^{5} + \dots

\frac{\partial}{\partial y} (4 x^{3} y^{3} - 2)

f (x) = \frac{4 + cot ( x )}{7 - tan ( x )}

5 t

\frac{6}{s ( s + 1 ) ( s + 2 ) + 6}

\int sin (3) x^{2} d x

What is maclaurin ln((1+x)/(1-x)) ?
The answer to maclaurin ln((1+x)/(1-x)) is 2x+2/3 x^3+2/5 x^5+\ldots