What is area-x^2+10,-sqrt(10),-1 ?

The answer to area-x^2+10,-sqrt(10),-1 is -(-1+10sqrt(10))/3-10+10sqrt(10)

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area-x^2+10,-sqrt(10),-1

area

- x^{2} + 10, - 10, - 1

- \frac{- 1 + 10 10}{3} - 10 + 1010

Decimal Notation

11.41518 \dots

Solution steps

Apply the area formula:

\int_{- 10}^{- 1} - x^{2} + 10 d x

Solve

\int_{- 10}^{- 1} - x^{2} + 10 d x : - \frac{- 1 + 10 10}{3} - 10 + 1010

The area is:

= - \frac{- 1 + 10 10}{3} - 10 + 1010

\int \frac{1}{sin ^{2} ( x ) \cdot cos ^{2} ( x )} d x

y^{^{''}} + 6 y^{^{'}} + 9 y = \frac{e ^{- 3 x}}{x}

n = 1 \sum \infty 0

n = 1 \sum \infty (\frac{e}{10})^{n}

What is area-x^2+10,-sqrt(10),-1 ?
The answer to area-x^2+10,-sqrt(10),-1 is -(-1+10sqrt(10))/3-10+10sqrt(10)