What is the integral from 0 to 1 of xsqrt(1+4x^2) ?

The integral from 0 to 1 of xsqrt(1+4x^2) is (5sqrt(5)-1)/(12)

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integral from 0 to 1 of xsqrt(1+4x^2)

\int_{0}^{1} x 1 + 4 x^{2} d x

\frac{5 5 - 1}{12}

Decimal Notation

0.84836 \dots

Solution steps

\int_{0}^{1} x 1 + 4 x^{2} d x

Apply u-substitution

: \int_{1}^{5} \frac{u}{8} d u

= \int_{1}^{5} \frac{u}{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int_{1}^{5} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{5}

= \frac{1}{8} [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{5}

Compute the boundaries:

\frac{10 5}{3} - \frac{2}{3}

= \frac{1}{8} (\frac{10 5}{3} - \frac{2}{3})

Simplify

= \frac{5 5 - 1}{12}

\frac{\partial}{\partial x} (x^{2} - 5 x y)

f (x) = x^{1.7}

x \to - 4 lim (\frac{x ^{2} + 9}{x + 2})

\int 16 e^{u} d u

y^{^{''}} - 4 y^{^{'}} - x + 2 = 0

What is the integral from 0 to 1 of xsqrt(1+4x^2) ?
The integral from 0 to 1 of xsqrt(1+4x^2) is (5sqrt(5)-1)/(12)