What is area y=sin^2(x),y=sin^3(x) ?

The answer to area y=sin^2(x),y=sin^3(x) is pi/2-4/3

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area y=sin^2(x),y=sin^3(x)

area

y = sin^{2} (x), y = sin^{3} (x)

\frac{π}{2} - \frac{4}{3}

Decimal Notation

0.23746 \dots

Solution steps

Apply the area formula:

\int_{0}^{π} sin^{2} (x) - sin^{3} (x) d x

Solve

\int_{0}^{π} sin^{2} (x) - sin^{3} (x) d x : \frac{π}{2} - \frac{4}{3}

The area is:

= \frac{π}{2} - \frac{4}{3}

\int \frac{4}{4 x ^{2} + 20 x + 34} d x

\int_{0}^{r} - π r^{2} x d x

\int 8 x^{7} e^{2 x^{8}} d x

arccos (a x)

\frac{\partial}{\partial x} (x^{2} + y^{2} + 10)

What is area y=sin^2(x),y=sin^3(x) ?
The answer to area y=sin^2(x),y=sin^3(x) is pi/2-4/3