What is (\partial)/(\partial x)(x^2+y^2+10) ?

The answer to (\partial)/(\partial x)(x^2+y^2+10) is 2x

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(\partial)/(\partial x)(x^2+y^2+10)

\frac{\partial}{\partial x} (x^{2} + y^{2} + 10)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + y^{2} + 10)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (10)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (10) = 0

= 2 x + 0 + 0

Simplify

= 2 x

\int_{0}^{\infty} 15 e^{- 5 x} d x

f (x) = 6 x - x^{2}, (1, 5)

f (x) = \frac{1}{x + 8}

y^{^{'}} - y = x e^{2 x} + 1

\frac{d}{d x} (5^{2 x^{3}})

What is (\partial)/(\partial x)(x^2+y^2+10) ?
The answer to (\partial)/(\partial x)(x^2+y^2+10) is 2x