What is the integral from 0 to infinity of 15e^{-5x} ?

The integral from 0 to infinity of 15e^{-5x} is 3

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integral from 0 to infinity of 15e^{-5x}

\int_{0}^{\infty} 15 e^{- 5 x} d x

3

Solution steps

\int_{0}^{\infty} 15 e^{- 5 x} d x

Compute the indefinite integral:

\int 15 e^{- 5 x} d x = - 3 e^{- 5 x} + C

Compute the boundaries:

\int_{0}^{\infty} 15 e^{- 5 x} d x = 0 - (- 3)

= 0 - (- 3)

Simplify

= 3

f (x) = 6 x - x^{2}, (1, 5)

f (x) = \frac{1}{x + 8}

y^{^{'}} - y = x e^{2 x} + 1

\frac{d}{d x} (5^{2 x^{3}})

x y^{^{'}} = 4 x^{2} - 2 y, y (1) = 3

What is the integral from 0 to infinity of 15e^{-5x} ?
The integral from 0 to infinity of 15e^{-5x} is 3