What is area sin^2(x),sin^3(x),0,pi ?

The answer to area sin^2(x),sin^3(x),0,pi is pi/2-4/3

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area sin^2(x),sin^3(x),0,pi

area

sin^{2} (x), sin^{3} (x), 0, π

\frac{π}{2} - \frac{4}{3}

Decimal Notation

0.23746 \dots

Solution steps

Apply the area formula:

\int_{0}^{π} sin^{2} (x) - sin^{3} (x) d x

Solve

\int_{0}^{π} sin^{2} (x) - sin^{3} (x) d x : \frac{π}{2} - \frac{4}{3}

The area is:

= \frac{π}{2} - \frac{4}{3}

\int 3 sin (x) + 2 - 3 e^{x} d x

f (x) = 4 x (1 - x), g (x) = 4 x - 4

\frac{d}{d x} (\frac{6 x ^{3} - 5 x ^{2} - 2 x}{4 x - 3 x ^{2}})

\frac{d}{d x} (5 x + \frac{100}{x})

x \to 2 lim (\frac{x + 2}{x - 2})

What is area sin^2(x),sin^3(x),0,pi ?
The answer to area sin^2(x),sin^3(x),0,pi is pi/2-4/3