What is the solution for y^'=(x^2+y^2)/(xy),y(1)=1 ?

The solution for y^'=(x^2+y^2)/(xy),y(1)=1 is y=xsqrt(2ln(x)+1)

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y^'=(x^2+y^2)/(xy),y(1)=1

y^{^{'}} = \frac{x ^{2} + y ^{2}}{x y}, y (1) = 1

y = x 2 ln (x) + 1

Solution steps

y^{'} (x) = \frac{x ^{2} + y ^{2}}{x y}

Solve Bernoulli ODE:

y = x 2 ln (x) + 1

y = x 2 ln (x) + 1

n = 1 \sum \infty 8 (\frac{3}{4})^{n}

\frac{\partial}{\partial x} (4 x^{2} y^{2})

(- 2, 1), (3, - 9)

\int \frac{1}{( r ^{2} + x ^{2} ) ^{\frac{3}{2}}} d x

\int x e^{1 + x^{2}} d x

What is the solution for y^'=(x^2+y^2)/(xy),y(1)=1 ?
The solution for y^'=(x^2+y^2)/(xy),y(1)=1 is y=xsqrt(2ln(x)+1)