What is the integral from 1/7 to 5 of 12xln(7x) ?

The integral from 1/7 to 5 of 12xln(7x) is 12(-306/49+25/2 ln(35))

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integral from 1/7 to 5 of 12xln(7x)

\int_{\frac{1}{7}}^{5} 12 x ln (7 x) d x

12 (- \frac{306}{49} + \frac{25}{2} ln (35))

Decimal Notation

458.36343 \dots

Solution steps

\int_{\frac{1}{7}}^{5} 12 x ln (7 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 12 \cdot \int_{\frac{1}{7}}^{5} x ln (7 x) d x

Apply Integration By Parts

: [\frac{1}{2} x^{2} ln (7 x) - \int \frac{x}{2} d x]_{\frac{1}{7}}^{5}

= 12 [\frac{1}{2} x^{2} ln (7 x) - \int \frac{x}{2} d x]_{\frac{1}{7}}^{5}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 12 [\frac{1}{2} x^{2} ln (7 x) - \frac{x ^{2}}{4}]_{\frac{1}{7}}^{5}

Compute the boundaries:

- \frac{306}{49} + \frac{25}{2} ln (35)

= 12 (- \frac{306}{49} + \frac{25}{2} ln (35))

y = e^{- 4 x}

x^{3} + 8, x + 8

\frac{6 x}{( x ^{2} + 1 )}

\frac{\partial}{\partial y} (\frac{e ^{x y}}{x + y})

\int \frac{1}{y ^{2} + y + 1} d y

What is the integral from 1/7 to 5 of 12xln(7x) ?
The integral from 1/7 to 5 of 12xln(7x) is 12(-306/49+25/2 ln(35))