What is the derivative of f(x)=x^2-3x+5 ?

The derivative of f(x)=x^2-3x+5 is 2x-3

What is the first derivative of f(x)=x^2-3x+5 ?

The first derivative of f(x)=x^2-3x+5 is 2x-3

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derivative of

f (x) = x^{2} - 3 x + 5

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5) = 0

= 2 x - 3 + 0

Simplify

= 2 x - 3

x \to 0 + lim (e^{- \frac{2}{x ^{3}}})

x, 9

f (x) = \frac{5}{x - 4}, at x = 3

\int t^{2} - 5 t + 4 d t

\int \frac{x ^{2}}{x} d x

What is the derivative of f(x)=x^2-3x+5 ?
The derivative of f(x)=x^2-3x+5 is 2x-3
What is the first derivative of f(x)=x^2-3x+5 ?
The first derivative of f(x)=x^2-3x+5 is 2x-3