en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 3 of 6-2x

Solution

\int_{0}^{3} 6 - 2 x d x

Solution

9

Solution steps

\int_{0}^{3} 6 - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 6 d x - \int_{0}^{3} 2 x d x

\int_{0}^{3} 6 d x = 18

\int_{0}^{3} 2 x d x = 9

= 18 - 9

Simplify

= 9

Popular Examples

integral of (3x+1)(2x-5)^2

\int (3 x + 1) (2 x - 5)^{2} d x

integral of 1/((x-1)(x+2))

\int \frac{1}{( x - 1 ) ( x + 2 )} d x

integral of 2xy+3x^2

\int 2 x y + 3 x^{2} d x

integral from 0 to 2 of (2x-1)

\int_{0}^{2} (2 x - 1) d x

integral of x/(\sqrt[3]{2-4x^2)}

Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of 6-2x ?
The integral from 0 to 3 of 6-2x is 9