What is the integral of 1/(sqrt(81-x^2)) ?

The integral of 1/(sqrt(81-x^2)) is arcsin(1/9 x)+C

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integral of 1/(sqrt(81-x^2))

\int \frac{1}{81 - x ^{2}} d x

arcsin (\frac{1}{9} x) + C

Solution steps

\int \frac{1}{81 - x ^{2}} d x

Apply Trigonometric Substitution

: \int 1 d u

= \int 1 d u

Integral of a constant:

\int a d x = a x

= 1 \cdot u

Substitute back

u = arcsin (\frac{1}{9} x)

= 1 \cdot arcsin (\frac{1}{9} x)

Simplify

= arcsin (\frac{1}{9} x)

Add a constant to the solution

= arcsin (\frac{1}{9} x) + C

\frac{d}{d x} ((2 + x sin (3 x))^{10})

\frac{d}{d x} ((sin^{2} (x) + 1)^{x})

4 t

\frac{d}{d x} (sin^{3} (3 x - 1))

e^{x}, 5

What is the integral of 1/(sqrt(81-x^2)) ?
The integral of 1/(sqrt(81-x^2)) is arcsin(1/9 x)+C