What is the derivative of sin^3(3x-1) ?

The derivative of sin^3(3x-1) is 9sin^2(3x-1)cos(3x-1)

What is the first derivative of sin^3(3x-1) ?

The first derivative of sin^3(3x-1) is 9sin^2(3x-1)cos(3x-1)

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\frac{d}{d x} (sin^{3} (3 x - 1))

9 sin^{2} (3 x - 1) cos (3 x - 1)

Solution steps

\frac{d}{d x} (sin^{3} (3 x - 1))

Apply the chain rule:

3 (sin (3 x - 1))^{2} \frac{d}{d x} (sin (3 x - 1))

= 3 (sin (3 x - 1))^{2} \frac{d}{d x} (sin (3 x - 1))

\frac{d}{d x} (sin (3 x - 1)) = cos (3 x - 1) \cdot 3

= 3 (sin (3 x - 1))^{2} cos (3 x - 1) \cdot 3

Simplify

= 9 sin^{2} (3 x - 1) cos (3 x - 1)

e^{x}, 5

x \to 3 lim (\frac{∣ x - 1 ∣}{x - 1})

\frac{d}{d x} (\frac{x y ^{2}}{x ^{2} + y ^{2}})

\int \frac{e ^{x}}{( e ^{x} + 1 )} d x

\int 4 cos (\frac{x}{2}) d x

What is the derivative of sin^3(3x-1) ?
The derivative of sin^3(3x-1) is 9sin^2(3x-1)cos(3x-1)
What is the first derivative of sin^3(3x-1) ?
The first derivative of sin^3(3x-1) is 9sin^2(3x-1)cos(3x-1)