What is the tangent of f(x)= 9/x ?

The tangent of f(x)= 9/x is y=-9/(a_{0)^2}x+(18)/(a_{0)}

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tangent of f(x)= 9/x

tangent of

f (x) = \frac{9}{x}

y = - \frac{9}{a _{0}^{2}} x + \frac{18}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{9}{a _{0}})

Find the slope of

f (x) = \frac{9}{x} : \frac{df ( x )}{d x} = - \frac{9}{x ^{2}}

Compute the slope of

f (x) = \frac{9}{x}

x = a_{0} : m = - \frac{9}{a _{0}^{2}}

Find the line with slope m=

- \frac{9}{a _{0}^{2}}

and passing through

(a_{0}, \frac{9}{a _{0}}) : y = - \frac{9}{a _{0}^{2}} x + \frac{18}{a _{0}}

y = - \frac{9}{a _{0}^{2}} x + \frac{18}{a _{0}}

\int (sin^{2} (2 x) cos^{4} (2 x)) d x

x \to - 6 lim (f (x))

\frac{d}{d x} (cos^{2} (4 x + 1))

\frac{d}{d x} (- 2 a sin (2 x))

\int \frac{x ^{5}}{x ^{6} - 3} d x

What is the tangent of f(x)= 9/x ?
The tangent of f(x)= 9/x is y=-9/(a_{0)^2}x+(18)/(a_{0)}