What is the derivative of cos^2(4x+1) ?

The derivative of cos^2(4x+1) is -8cos(4x+1)sin(4x+1)

What is the first derivative of cos^2(4x+1) ?

The first derivative of cos^2(4x+1) is -8cos(4x+1)sin(4x+1)

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\frac{d}{d x} (cos^{2} (4 x + 1))

- 8 cos (4 x + 1) sin (4 x + 1)

Solution steps

\frac{d}{d x} (cos^{2} (4 x + 1))

Apply the chain rule:

2 cos (4 x + 1) \frac{d}{d x} (cos (4 x + 1))

= 2 cos (4 x + 1) \frac{d}{d x} (cos (4 x + 1))

\frac{d}{d x} (cos (4 x + 1)) = - sin (4 x + 1) \cdot 4

= 2 cos (4 x + 1) (- sin (4 x + 1) \cdot 4)

Simplify

= - 8 cos (4 x + 1) sin (4 x + 1)

\frac{d}{d x} (- 2 a sin (2 x))

\int \frac{x ^{5}}{x ^{6} - 3} d x

f (x) = 9 e^{x} (cos (x) - sin (x))

\frac{d}{d x} (x^{4} sin (x) tan (x))

- 4 x^{2} + 7 x

What is the derivative of cos^2(4x+1) ?
The derivative of cos^2(4x+1) is -8cos(4x+1)sin(4x+1)
What is the first derivative of cos^2(4x+1) ?
The first derivative of cos^2(4x+1) is -8cos(4x+1)sin(4x+1)