What is the derivative of f(x)=9e^x(cos(x)-sin(x)) ?

The derivative of f(x)=9e^x(cos(x)-sin(x)) is -18e^xsin(x)

What is the first derivative of f(x)=9e^x(cos(x)-sin(x)) ?

The first derivative of f(x)=9e^x(cos(x)-sin(x)) is -18e^xsin(x)

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derivative of

f (x) = 9 e^{x} (cos (x) - sin (x))

- 18 e^{x} sin (x)

Solution steps

\frac{d}{d x} (9 e^{x} (cos (x) - sin (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{x} (cos (x) - sin (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cos (x) - sin (x)

= 9 (\frac{d}{d x} (e^{x}) (cos (x) - sin (x)) + \frac{d}{d x} (cos (x) - sin (x)) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (x) - sin (x)) = - sin (x) - cos (x)

= 9 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x})

Simplify

9 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x}) : - 18 e^{x} sin (x)

= - 18 e^{x} sin (x)

\frac{d}{d x} (x^{4} sin (x) tan (x))

- 4 x^{2} + 7 x

n = 3 \sum \infty e^{5 - 4 n}

\int \frac{- x}{( x ^{2} + 1 ) ^{2}} d x

x \to - 3 lim (\frac{3 - ∣ x ∣}{x + 3})

What is the derivative of f(x)=9e^x(cos(x)-sin(x)) ?
The derivative of f(x)=9e^x(cos(x)-sin(x)) is -18e^xsin(x)
What is the first derivative of f(x)=9e^x(cos(x)-sin(x)) ?
The first derivative of f(x)=9e^x(cos(x)-sin(x)) is -18e^xsin(x)