What is the solution for y^'=(x^2+xy+y^2)/(x^2) ?

The solution for y^'=(x^2+xy+y^2)/(x^2) is y=tan(ln(x)+c_{1})x

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y^'=(x^2+xy+y^2)/(x^2)

y^{^{'}} = \frac{x ^{2} + x y + y ^{2}}{x ^{2}}

y = tan (ln (x) + c_{1}) x

Solution steps

y^{'} (x) = \frac{x ^{2} + x y + y ^{2}}{x ^{2}}

Solve using substitution:

y = tan (ln (x) + c_{1}) x

y = tan (ln (x) + c_{1}) x

d y = (x - 2 x y) d x

x^{2} + 4 x - 8

x \to 0 + lim (x^{5} ln (x))

x \to 1 - lim (6 x - 2)

\frac{\partial}{\partial x} (3 x^{2} y^{2} + \frac{x}{y})

What is the solution for y^'=(x^2+xy+y^2)/(x^2) ?
The solution for y^'=(x^2+xy+y^2)/(x^2) is y=tan(ln(x)+c_{1})x