What is the sum from n=1 to infinity of 5/n ?

The sum from n=1 to infinity of 5/n is diverges

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sum from n=1 to infinity of 5/n

n = 1 \sum \infty \frac{5}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{5}{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 1 \sum \infty \frac{1}{n}

Apply Cauchy's Convergence Condition:

diverges

= 5 diverges

= diverges

\int e x^{2} d x

e^{\frac{t}{9}} cos (\frac{t}{9})

\int \frac{8 x + 1}{x ^{2} + 1} d x

f (x) = \frac{8}{x}, at x = 5

y^{^{''}} + y = 9 sin (x)

What is the sum from n=1 to infinity of 5/n ?
The sum from n=1 to infinity of 5/n is diverges