What is the derivative of ln(sin(2x)) ?

The derivative of ln(sin(2x)) is 2cot(2x)

What is the first derivative of ln(sin(2x)) ?

The first derivative of ln(sin(2x)) is 2cot(2x)

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derivative of

ln (sin (2 x))

2 cot (2 x)

Solution steps

\frac{d}{d x} (ln (sin (2 x)))

Apply the chain rule:

\frac{1}{sin ( 2 x )} \frac{d}{d x} (sin (2 x))

= \frac{1}{sin ( 2 x )} \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= \frac{1}{sin ( 2 x )} cos (2 x) \cdot 2

Simplify

\frac{1}{sin ( 2 x )} cos (2 x) \cdot 2 : 2 cot (2 x)

= 2 cot (2 x)

y^{^{'}} - k y = 0

y = x (9.3)

\int x^{2} \cdot sin (x) d x

y^{^{'}} - \frac{y}{x} = 2

y^{^{''}} - 7 y^{^{'}} + 2 y = t e^{t}

What is the derivative of ln(sin(2x)) ?
The derivative of ln(sin(2x)) is 2cot(2x)
What is the first derivative of ln(sin(2x)) ?
The first derivative of ln(sin(2x)) is 2cot(2x)