What is the integral from 3 to infinity of x/(x^2+1) ?

The integral from 3 to infinity of x/(x^2+1) is diverges

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integral from 3 to infinity of x/(x^2+1)

\int_{3}^{\infty} \frac{x}{x ^{2} + 1} d x

diverges

Solution steps

\int_{3}^{\infty} \frac{x}{x ^{2} + 1} d x

Compute the indefinite integral:

\int \frac{x}{x ^{2} + 1} d x = \frac{1}{2} ln x^{2} + 1 + C

Compute the boundaries:

\int_{3}^{\infty} \frac{x}{x ^{2} + 1} d x =

diverges

= diverges

x \to - 3 lim (\frac{5 x ^{2}}{x + 3})

\frac{\partial}{\partial y} (x + y^{2})

\int 6 x \cdot csc^{2} (8 x^{2}) d x

x \to 0 + lim (e^{\frac{- 1}{x}})

\frac{\partial}{\partial x} (x^{2} + y^{2} + z)

What is the integral from 3 to infinity of x/(x^2+1) ?
The integral from 3 to infinity of x/(x^2+1) is diverges