What is (\partial)/(\partial y)(x+y^2) ?

The answer to (\partial)/(\partial y)(x+y^2) is 2y

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(\partial)/(\partial y)(x+y^2)

\frac{\partial}{\partial y} (x + y^{2})

2 y

Solution steps

\frac{\partial}{\partial y} (x + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 + 2 y

Simplify

= 2 y

\int 6 x \cdot csc^{2} (8 x^{2}) d x

x \to 0 + lim (e^{\frac{- 1}{x}})

\frac{\partial}{\partial x} (x^{2} + y^{2} + z)

t \to 1 lim ((3 t - 1) (5 t^{2} + 2))

\frac{d}{d x} (sin (x) ln (9 x))

What is (\partial)/(\partial y)(x+y^2) ?
The answer to (\partial)/(\partial y)(x+y^2) is 2y