What is the integral of (sec^2(x)+2) ?

The integral of (sec^2(x)+2) is tan(x)+2x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (sec^2(x)+2)

\int (sec^{2} (x) + 2) d x

tan (x) + 2 x + C

Solution steps

\int sec^{2} (x) + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (x) d x + \int 2 d x

\int sec^{2} (x) d x = tan (x)

\int 2 d x = 2 x

= tan (x) + 2 x

Add a constant to the solution

= tan (x) + 2 x + C

x \to - 7 + lim (\frac{x - 4}{x + 7})

\frac{\partial}{\partial x} (7 + 8 x y)

x \to 0 lim (\frac{1}{2 x})

\frac{d}{d x} (5 x - e)

\frac{\partial}{\partial x} (\frac{6 x - 7 y}{y ^{2} + x ^{2}})

What is the integral of (sec^2(x)+2) ?
The integral of (sec^2(x)+2) is tan(x)+2x+C