en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x^2-2x,y=3x+6

Solution

area

y = x^{2} - 2 x, y = 3 x + 6

Solution

\frac{343}{6}

+1

Decimal Notation

57.16666 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{6} x^{2} - 2 x - (3 x + 6) d x

Solve

\int_{- 1}^{6} x^{2} - 2 x - (3 x + 6) d x : \frac{343}{6}

The area is:

= \frac{343}{6}

Popular Examples

integral of e^{-x}sin(4x)

\int e^{- x} sin (4 x) d x

(x^2+1)y^'+6x(y-1)=0,y(0)=8

(x^{2} + 1) y^{^{'}} + 6 x (y - 1) = 0, y (0) = 8

integral of (ln(y))^2

\int (ln (y))^{2} d y

area (x^2-1)(x^2-4),x=0,x=5 area

(x^{2} - 1) (x^{2} - 4), x = 0, x = 5

area xsqrt(4-x^2),0 area

x 4 - x^{2}, 0

Frequently Asked Questions (FAQ)

What is area y=x^2-2x,y=3x+6 ?
The answer to area y=x^2-2x,y=3x+6 is 343/6