What is area (x^2-1)(x^2-4),x=0,x=5 ?

The answer to area (x^2-1)(x^2-4),x=0,x=5 is 2198/5

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area (x^2-1)(x^2-4),x=0,x=5

area

(x^{2} - 1) (x^{2} - 4), x = 0, x = 5

\frac{2198}{5}

Decimal Notation

439.6

Solution steps

Apply the area formula:

\int_{0}^{5} x^{2} - 1 x^{2} - 4 d x

Solve

\int_{0}^{5} x^{2} - 1 x^{2} - 4 d x : \frac{2198}{5}

The area is:

= \frac{2198}{5}

x 4 - x^{2}, 0

x + y

\frac{d}{d x} (4 x (x^{2} + 1))

y = \frac{1}{x}, x = 2, y = - 1

\int_{- \infty}^{- 1} x e^{x} d x

What is area (x^2-1)(x^2-4),x=0,x=5 ?
The answer to area (x^2-1)(x^2-4),x=0,x=5 is 2198/5