What is the integral from-infinity to-1 of xe^x ?

The integral from-infinity to-1 of xe^x is -2/e

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integral from-infinity to-1 of xe^x

\int_{- \infty}^{- 1} x e^{x} d x

- \frac{2}{e}

Decimal Notation

- 0.73575 \dots

Solution steps

\int_{- \infty}^{- 1} x e^{x} d x

Compute the indefinite integral:

\int x e^{x} d x = e^{x} x - e^{x} + C

Compute the boundaries:

\int_{- \infty}^{- 1} x e^{x} d x = - \frac{2}{e} - 0

= - \frac{2}{e} - 0

Simplify

= - \frac{2}{e}

x \to 6 lim (9 x + x^{2} (3 x + 5))

y = (2 x - 1) (3 x + 4) (x + 7)

\int t - 8 cos (t) d t

\int \frac{x ^{3} - x ^{2} - 2 x}{4 x - 2} d x

x \to \infty + lim (\frac{lo g _{6} ( x )}{lo g _{8} ( x )})

What is the integral from-infinity to-1 of xe^x ?
The integral from-infinity to-1 of xe^x is -2/e