What is the sum from n=0 to infinity of (3^n)/(n!) ?

The sum from n=0 to infinity of (3^n)/(n!) is converges

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sum from n=0 to infinity of (3^n)/(n!)

n = 0 \sum \infty \frac{3 ^{n}}{n !}

converges

Solution steps

n = 0 \sum \infty \frac{3 ^{n}}{n !}

Apply Series Ratio Test:

converges

= converges

\frac{d}{d x} ((x) cos (x) sin (x))

\frac{\partial}{\partial x} (e^{2 (2 x + y)})

ln (x^{2} - 1)

n = 0 \sum \infty n x^{n - 1}

\frac{d}{d x} (x^{\frac{- 5}{9}})

What is the sum from n=0 to infinity of (3^n)/(n!) ?
The sum from n=0 to infinity of (3^n)/(n!) is converges