What is the integral of (7/(x^5)+8e^{2x}-4x) ?

The integral of (7/(x^5)+8e^{2x}-4x) is -7/(4x^4)+4e^{2x}-2x^2+C

Popular >

integral of (7/(x^5)+8e^{2x}-4x)

\int (\frac{7}{x ^{5}} + 8 e^{2 x} - 4 x) d x

- \frac{7}{4 x ^{4}} + 4 e^{2 x} - 2 x^{2} + C

Solution steps

\int \frac{7}{x ^{5}} + 8 e^{2 x} - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{7}{x ^{5}} d x + \int 8 e^{2 x} d x - \int 4 x d x

\int \frac{7}{x ^{5}} d x = - \frac{7}{4 x ^{4}}

\int 8 e^{2 x} d x = 4 e^{2 x}

\int 4 x d x = 2 x^{2}

= - \frac{7}{4 x ^{4}} + 4 e^{2 x} - 2 x^{2}

Add a constant to the solution

= - \frac{7}{4 x ^{4}} + 4 e^{2 x} - 2 x^{2} + C

n = 1 \sum \infty \frac{- 2 ^{n}}{n ^{7}}

\frac{d}{d x} (\frac{12 - 3 y - 2 x}{4})

y = x (x^{2} + 1)^{3}

\int (cos (n x)) d x

\int_{- 1}^{2} (1 - x) d x

What is the integral of (7/(x^5)+8e^{2x}-4x) ?
The integral of (7/(x^5)+8e^{2x}-4x) is -7/(4x^4)+4e^{2x}-2x^2+C