What is the derivative of (-7/(x^2)) ?

The derivative of (-7/(x^2)) is (14)/(x^3)

What is the first derivative of (-7/(x^2)) ?

The first derivative of (-7/(x^2)) is (14)/(x^3)

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\frac{d}{d x} (\frac{- 7}{x ^{2}})

\frac{14}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{- 7}{x ^{2}})

Simplify

\frac{- 7}{x ^{2}} : - \frac{7}{x ^{2}}

= \frac{d}{d x} (- \frac{7}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 7 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 7 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 7 (- 2 x^{- 2 - 1})

Simplify

- 7 (- 2 x^{- 2 - 1}) : \frac{14}{x ^{3}}

= \frac{14}{x ^{3}}

sin (3 t + \frac{π}{4})

e^{x} - x^{8}

\int cos (2 x + 5) d x

\frac{\partial}{\partial x} (cos (4 x y))

y = 6 x^{2} - 10 x - 5 x^{- 2}

What is the derivative of (-7/(x^2)) ?
The derivative of (-7/(x^2)) is (14)/(x^3)
What is the first derivative of (-7/(x^2)) ?
The first derivative of (-7/(x^2)) is (14)/(x^3)